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live demand report in US

G To Kg

 Aug    Medium opportunity   


General search term.
Might be referring to: the Graphical Unix Gnutella Client.
This is a seasonal trend that repeats every August.
This trend is forecasted to be growing in the next 2 years.

  

Track this trend
(Monitor this trend over time)

74K
searches/mo

 12 Months
Average: 39.69%
Trend: growing
MOM change: 0.12%
 5 Years
Average: 38.41%
Trend: growing
MOM change: 0.62%

Latest forum discussions

We tracked 7145 total in the last 3 months

molality of solution: Change in freezing point = Kf  m 3.07 °C = 1.86°C/m (m)m = 1.6505 mole solute / kg solvent Mass solute / kilogram water: 15.00 g / 0.05000 kg = 300.0 g solute / kg solvent Molar mass: 300 g/kg / 1.6505 mol/kg = 181.8 g/mol
Published on 2021-03-18 in the Science & Mathematics forum
This discussion is in English.
molality of solution: Change in freezing point = Kf  m 3.07 °C = 1.86°C/m (m)m = 1.6505 mole solute / kg solvent Mass solute / kilogram water: 15.00 g / 0.05000 kg = 300.0 g solute / kg solvent Molar mass: 300 g/kg / 1.6505 mol/kg = 181.8 g/mol
Published on 2021-03-18 in the Science and Mathematics forum
This discussion is in English.
molality of solution: Change in freezing point = Kf  m 3.07 °C = 1.86°C/m (m)m = 1.6505 mole solute / kg solvent Mass solute / kilogram water: 15.00 g / 0.05000 kg = 300.0 g solute / kg solvent Molar mass: 300 g/kg / 1.6505 mol/kg = 181.8 g/mol
Published on 2021-03-18 in the Science and Mathematics forum
This discussion is in English.
molality of solution: Change in freezing point = Kf  m 3.07 °C = 1.86°C/m (m)m = 1.6505 mole solute / kg solvent Mass solute / kilogram water: 15.00 g / 0.05000 kg = 300.0 g solute / kg solvent Molar mass: 300 g/kg / 1.6505 mol/kg = 181.8 g/mol
Published on 2021-03-18 in the Science and Mathematics forum
This discussion is in English.
molality of solution: Change in freezing point = Kf  m 3.07 °C = 1.86°C/m (m)m = 1.6505 mole solute / kg solvent Mass solute / kilogram water: 15.00 g / 0.05000 kg = 300.0 g solute / kg solvent Molar mass: 300 g/kg / 1.6505 mol/kg = 181.8 g/mol
Published on 2021-03-18 in the Science and Mathematics forum
This discussion is in English.
... 2877 kJ. m(C4H10) = 1 kg = 1000g M(C4H10) = (12,011... + 1,008 * 10) = 58,12 g/mol n(C4H10) = 1000g / 58...,12 g/mol ≈ 17,2 mol Energin... värme när man förbränner 1 kg butan. Min magkänsla säger att...
Published on 2021-03-12 in the Kemi 1 forum
This discussion is in Swedish.
... 2877 kJ. m(C4H10) = 1 kg = 1000g M(C4H10) = (12,011... + 1,008 * 10) = 58,12 g/mol n(C4H10) = 1000g / 58...,12 g/mol ≈ 17,2 mol Energin... värme när man förbränner 1 kg butan. Min magkänsla säger att...
Published on 2021-03-12 in the Kemi 1 forum
This discussion is in Swedish.
(0.0240 kg) x (1000 g/kg) / (142.0421 g Na2SO4/mol) = 0.169 mol Na2SO4
Published on 2021-03-21 in the Science and Mathematics forum
This discussion is in Unknown.
(0.0240 kg) x (1000 g/kg) / (142.0421 g Na2SO4/mol) = 0.169 mol Na2SO4
Published on 2021-03-21 in the Science and Mathematics forum
This discussion is in Unknown.
(0.0240 kg) x (1000 g/kg) / (142.0421 g Na2SO4/mol) = 0.169 mol Na2SO4
Published on 2021-03-21 in the Science and Mathematics forum
This discussion is in Unknown.
(0.0240 kg) x (1000 g/kg) / (142.0421 g Na2SO4/mol) = 0.169 mol Na2SO4
Published on 2021-03-21 in the Science and Mathematics forum
This discussion is in Unknown.
(0.0240 kg) x (1000 g/kg) / (142.0421 g Na2SO4/mol) = 0.169 mol Na2SO4
Published on 2021-03-21 in the Science & Mathematics forum
This discussion is in Unknown.
(0.0240 kg) x (1000 g/kg) / (142.0421 g Na2SO4/mol) = 0.169 mol Na2SO4
Published on 2021-03-21 in the Science & Mathematics forum
This discussion is in Unknown.
(0.0240 kg) x (1000 g/kg) / (142.0421 g Na2SO4/mol) = 0.169 mol Na2SO4
Published on 2021-03-21 in the Science and Mathematics forum
This discussion is in Unknown.
(0.0240 kg) x (1000 g/kg) / (142.0421 g Na2SO4/mol) = 0.169 mol Na2SO4
Published on 2021-03-21 in the Science and Mathematics forum
This discussion is in Unknown.
Jag försökte lösa denna genom att multiplicera 25 dm^3 och 1.555 g/ml och fick ungefär 39 kg vilket är rätt svar men undrar om detta var rätt sätt att lösa uppgiften på eller om jag bara hade tur. Förstår inte riktigt varför temperaturen nämndes om den inte ska användas för att lösa uppgiften.
Published on 2021-02-07 in the Kemi 1 forum
This discussion is in Swedish.
Jag försökte lösa denna genom att multiplicera 25 dm^3 och 1.555 g/ml och fick ungefär 39 kg vilket är rätt svar men undrar om detta var rätt sätt att lösa uppgiften på eller om jag bara hade tur. Förstår inte riktigt varför temperaturen nämndes om den inte ska användas för att lösa uppgiften.
Published on 2021-02-07 in the Kemi 1 forum
This discussion is in Swedish.
Hi, this is my second pregnancy and I'm 20w1d pregnant mom. I've just met my doctor this evening and had long anatomy scan. My baby weight is 403 g. even though I've gained 1.5 kg. from last month. So, I looked it up on internet and compared with baby's weight on this app (280g at 20w1d) Is my baby a big boy? (my first child born with weight 3,870g.) How about your kid?
Published on 2021-04-22 in the expecting 2nd child forum
This discussion is in English.
Hi, this is my second pregnancy and I'm 20w1d pregnant mom. I've just met my doctor this evening and had long anatomy scan. My baby weight is 403 g. even though I've gained 1.5 kg. from last month. So, I looked it up on internet and compared with baby's weight on this app (280g at 20w1d) Is my baby a big boy? (my first child born with weight 3,870g.) How about your kid?
Published on 2021-04-22 in the expecting 2nd child forum
This discussion is in English.